The oxidation number of sulfur in the compound Al 2 (SO 4) 3 is The oxidation number of SO4 group is -2, Since oxidation number of oxygen is -2 and the oxidation number of sulphur is +6 (atomic number of sulphur is 16 so electronic configuration is 1s2 2s2 2p6 3s2 3p6, in outermost shell there are 6 valence electrons). The oxidation number in Sulfur in BaSO4 is S=6. Since you're dealing with a neutral compound, the sum of the oxidation numbers of all the atoms that form said compound must be zero. Add your answer and earn points. So oxidation number of SO42- is; To find this oxidation number, it is important to know that the sum of the oxidation numbers of atoms in compounds that are neutral must equal zero. SO4 has charge of -2. Oxidation number of oxygen is -2 because it contains 6 electrons in its outer most orbit. The oxidation number for sulfur in SO2 is +4. O is -2 almost always and is -2 in this case as well. Oxidation number of sulphur is to found so let the oxidation number of sulphur be x. What is my next step?-FeSO4 charge is neutral SO4 is 2-, oxygen is -2 each*4 = -8 Fe is 2+ You can set it up like this S + 4(-2) = -2 S + -8 = -2 S = -2 + 8 S = 6 C Oxidation number of Sulfur in FeSO4 - Science Mathematics For the compounds having charge like in SO42- the addition of the oxidation number is equal to the charge possessed by the compound. In the compound sulfur dioxide (SO2), the oxidation number of oxygen is -2. So oxidation number of SO42- is; In the compound sulfur dioxide (SO2), the oxidation number of oxygen is -2. answers: -2 +4 +6 +8. The oxidation number for sulfur in SO2 is +4. Al2(SO4)3, aluminum sulfate SO4^- is always -2, and there are three which gives total negative charge of -6, therefore each aluminum must be +3. Using the rule and adding the oxidation numbers in the compound, the equation becomes x +(-4 ) = 0. Therefore, as S2^+ is being oxidized, S2O3^2- … Oxidation number of sulphur is to found so let the oxidation number of sulphur be x. The oxidation number of sulfur in each of the following is +6 except A) S2O4^2- B) SO3 C) Na2SO4 D) SO4^2- Get the answers you need, now! Chemistry. Pure element has zero oxidation number. The oxidation state of the sulfur is +4. SO2(g) + H2O(l) → H2SO3(l) What mass of sulfur dioxide is When forming ions it is equal the charge of ion.Atomic sulfur has oxidation number of 0. The oxidation states for sulfur and oxygen atom are determined from: electronegativities total charge "SO"_4^(2-) has a total charge of -2, and oxygen is more electronegative than sulfur. Elemental sulfur can be converted to sulfur dioxide by combustion in air. 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